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To calculate the moisture removal load of a dry room, the design parameters of temperature and humidity should be determined first.
Wet load for ventilation
When the room is dehumidified, the ventilation volume should be reduced to the minimum, usually the ventilation volume of the door opening and leakage or the ventilation volume needed by the indoor personnel. The air change per hour of a room with good sealing ability is at least 0.1 times/hour, and the air change of a room with poor sealing ability, such as the door is often switched on and off, can reach 0.3 times/hour. The ventilation volume is determined by ambient air parameters, and its wet load relation is as follows:
The Mv = 1.2 * V * (X1, X2) / 1000
Among them
Mv= new rheumatic load [Kg/h]
V= total ventilation volume
X1= Moisture content of outdoor air [g/Kg]- Check the enthalpy chart or table according to local meteorological conditions
X2= indoor air moisture content [g/Kg]- Check enthalpy moisture chart or table according to dry room design conditions
Human wet load
People produce wet loads when they breathe and when they sweat.
The wet load at rest is 0.05Kg/h, while the wet load at work is 0.1-0.3kg /h.
Wet load on water surface
The hotter the water, the more wet load it creates. Dry air and air currents passing over the surface of the water also cause it to evaporate quickly.
M w = delta l * A * (X1, X2) / 1000
Among them
Mw= Wet load of water surface [kg/h]
δ = evaporation coefficient, generally 25[Kg/(㎡h
A= Water meter area [㎡
X1= Moisture content of saturated air on the water surface, which can be obtained by referring to the table
X2= Indoor air moisture content [Kg/h]
Wet load of the product
Because there are too many factors, it is difficult to calculate the wet load of the product, which can be estimated step by step through experiments.
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